sqlite_current

(PHP 5)

sqlite_current

(no version information, might be only in CVS)

SQLiteResult->current

(no version information, might be only in CVS)

SQLiteUnbuffered->current -- Fetches the current row from a result set as an array

说明

array sqlite_current ( resource result [, int result_type [, bool decode_binary]] )

Object oriented style (method):

class SQLiteResult {

array current ( [int result_type [, bool decode_binary]] )

}class SQLiteUnbuffered {

array current ( [int result_type [, bool decode_binary]] )

}

sqlite_current() is identical to sqlite_fetch_array() except that it does not advance to the next row prior to returning the data; it returns the data from the current position only.

参数

result

The SQLite result resource. This parameter is not required when using the object-oriented method.

result_type

可选的 result_type 参数接受一个常量并决定返回的数组如何索引。用 SQLITE_ASSOC 只会返回关联索引(有名称字段)而 SQLITE_NUM 只会返回数字索引(有序字段数)。SQLITE_BOTH 会同时返回关联和数字索引。 SQLITE_BOTH 是本函数的默认值。

decode_binary

decode_binary 参数设为 TRUE(默认值)时,PHP 将解码那些由 sqlite_escape_string() 编码的数据。通常应保留此值为其默认值,除非在操作其它支持 sqlite 程序建立的数据库时。

返回值

Returns an array of the current row from a result set; FALSE if the current position is beyond the final row.

SQLITE_ASSOCSQLITE_BOTH 返回的列名会根据 sqlite.assoc_case 配置选项的值来决定大小写。

参见

sqlite_seek()
sqlite_next()
sqlite_fetch_array()